Question

¿cuál será el volumen que ocupara 2g de oxígeno molecular a 20C y 728Torr?

Answer 1

P x V = n  x  R  x  T

Moles (n)= 2 g / 32 g/mol

n= 0.0625 mol

T = 20 ºC + 273 = 293 K

R = 0.0821 ( L x atm) /(mol x K)

P = 728 Torr = 0.958 atm.

v = n x R xT
     ````````````
           P

V = 0.0625 mol  x   293 K   x  0.0821 ( L x atm) /(mol x K)
       ````````````````````````````````````````````````````````````````````````
                               0.958 atm

V = 1.56 LITROS