Question

resuelva estos ejercicios
(2/3)^2.√9 .(√(81/4).(1/2)^2 )

(2/3)^2 (1-3/2+√(1/8+7/16)).(1+ 2/3)^3

[(1-2/3)/(2-1/3) (2/3-5/2)-√(3-11/9)]

(1/2-2)^2.√(2.(-1/2)^2.2^(-2) )

Answer 1

Respuesta:

(4/9×3)×(9/2×1/4)

(4/3)×(9/8)

\frac{4*9}{3*8}

3∗8

4∗9

3/23/2