Question

resolver las siguientes ecuaciones

Answer 1

Respuesta:

$1$

$a)2x + 10 = 16 \\ 2x = 16 - 10 \\ 2x = 6 \\ x = \frac{6}{2} \\ x = 3$

$b)10x - 8 = 8x \\10x - 8x = 8 \\ 2x = 8 \\ x = \frac{8}{2} \\ x = 4$

$2$

$a)3(x - 1) = x + 1 1\\ 3x - 3 = x + 11 \\ 3x - x = 11 + 3 \\ 2x = 14 \\ x = \frac{14}{2} \\ x = 7$

$b)3x + 7 = 2(8 + x) \\ 3x + 7 = 16 + 2x \\ 3x - 2x = 16 - 7 \\ x = 9$

$3$

$a)3x + \frac{x}{2} = 4 \\ 2(3x + \frac{x}{2} ) = 2 \times 4 \\ 6x + x = 8 \\ 7x = 8 \\ x = \frac{8}{7}$

$b)5 + \frac{2x}{3} = 4x - 7 \\ 3(5 + \frac{2x}{3} ) = 3(4x - 7) \\ 15 + 2x = 12x - 21 \\ 15 + 21 = 12x - 2x \\ 36 = 10x \\ \frac{36}{10} = x \\ \frac{18}{5} = x$

$4$

$Altura ⇒x =5cm \\Base ⇒2x = 2 \times 5 = 10cm \\2 (2x + x) = 30 \\ 4x + 2x = 30 \\ 6x = 30 \\ x = \frac{30}{6} \\ x = 5$