Question

(15x+11y=32 ... 7y-9x=8) usando metodo de determinantes

Answer 1

Respuesta:

x=0,66 y=2

Explicación paso a paso:

15x+11y=32

-9x + 7y=8

colocamos solo coeficientes

x y R

A = | 15 11 | 32 |

| -9 7 | 8 |

Ax= | 32 11 |

| 8 7 |

Ay= | 15 32 |

| -9 8 |

det(A) = 15*7 - -9*11

detA = 105 + 99

detA = 204

det(Ax)= 32*7 -11*8

det(Ax)=224-88

det(Ax)=136

det(Ay)=15*8 - -9*32

det(Ay)= 120+288

det(Ay)= 408

para hallar "x"

x= det (Ax)/det(A)

x=136/204

x=0,66

y= det (Ay)/det(A)

y=408/204

y=2