Question

Regalo puntos

Realiza estas operaciones:

a) 13/5-(1/2+1/6)

b) 4-(2-1/2)+(3-1/3)

c) 25/9-(1/3+1/6)

d) 6/5-(3/10-1/4)

e) 4/3-(3/8+1/2)+(5/2-1/6)

f) 3/10-1/5+(2+2/5-5/3)

g) 5/6-(3/4-1/3)+(2/3-1/9)​

Answer 1

Respuesta:

$a) \frac{13}{5} - ( \frac{1}{2} + \frac{1}{6} ) = \frac{13}{5} - ( \frac{3}{6} + \frac{1}{6} ) = \frac{13}{5} - \frac{4}{6} = \frac{13}{5} - \frac{2}{3} = \frac{39}{15} - \frac{10}{15} = \frac{29}{15}$

$b)4 -(2 - \frac{1}{2} ) + (3 - \frac{1}{3} ) = 4 - ( \frac{4}{2} - \frac{1}{2} ) + ( \frac{9}{3} - \frac{1}{3} ) = 4 - \frac{3}{2} + \frac{8}{3} = \frac{24}{6} - \frac{9}{6} + \frac{16}{6} = \frac{31}{6}$

$c) \frac{25}{9} - ( \frac{1}{3} + \frac{1}{6} ) = \frac{25}{9} - ( \frac{2}{6} + \frac{1}{6} ) = \frac{25}{9} - \frac{3}{6} = \frac{25}{9} - \frac{1}{2} = \frac{50}{18} - \frac{9}{18} = \frac{41}{18}$

$d) \frac{6}{5} - ( \frac{3}{10} - \frac{1}{4} ) = \frac{6}{5} - ( \frac{6}{20} - \frac{5}{20} ) = \frac{6}{5} - \frac{1}{20} = \frac{24}{20} - \frac{1}{20} = \frac{23}{20}$

$e) \frac{4}{3} - ( \frac{3}{8} + \frac{1}{2} ) + ( \frac{5}{2} - \frac{1}{6} ) = \frac{4}{3} - ( \frac{3}{8} + \frac{4}{8} ) + ( \frac{15}{6} - \frac{1}{6} ) = \frac{4}{3} - \frac{7}{8} + \frac{14}{6} = \frac{32}{24} - \frac{21}{24} + \frac{56}{24} = \frac{67}{24}$

$f) \frac{3}{10} - \frac{1}{5} + (2 + \frac{2}{5} - \frac{5}{3} ) = \frac{3}{10} - \frac{1}{5} + ( \frac{30}{15} + \frac{6}{15} - \frac{25}{15} ) = \frac{3}{10} - \frac{1}{5} + \frac{11}{15} = \frac{9}{30} - \frac{6}{30} + \frac{22}{30} = \frac{25}{30} = \frac{5}{6}$

$g) \frac{5}{6} - ( \frac{3}{4} - \frac{1}{3} ) + ( \frac{2}{3} - \frac{1}{9} ) = \frac{5}{6} - ( \frac{9}{12} - \frac{4}{12} ) + ( \frac{6}{9} - \frac{1}{9} ) = \frac{5}{6} - \frac{5}{12} + \frac{5}{9} = \frac{30}{36} - \frac{15}{36} + \frac{20}{36} = \frac{35}{36}$