Question

x+y/x-y=7/3

x+4/y+4=13/6

Answer 1

$\frac{x+y}{x-y} = \frac{7}{3}\\\\3(x+y) = 7(x - y)\\\\3x + 3y = 7x - 7y\\\\3y + 7y = 7x -3x\\\\10y = 4x\\\\\frac{10y}{4} = x\\\\\frac{5y}{2} = x$

$\frac{x+4}{y+4} = \frac{13}{6}\\\\6(x+4)= 13(y+4)\\\\6x + 24 = 13y + 52\\\\6x - 13y = 52 - 24\\\\6x - 13y = 28\\\\6(\frac{5y}{2} ) - 13y = 28\\\\3(5y) - 13y = 28\\\\15y - 13 y = 28\\\\2y = 28\\\\y = \frac{28}{2}\\\\y = 14$

$\frac{5y}{2 } = x\\\\\frac{5(14)}{2} = x\\\\5(7) = x\\\\35 = x$

Eternamente axllxa