Question

calcular la composicion porcentual de Al(0H)3

Answer 1

masa molecular

Al = 1 x 27 g = 27 g/mol
O=  3 x 16 =  48 g/mol
H =   3  x  1 = 3 g/mol
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             Mm= 78 g/mol

ALUMINIO

78 g -------- 100%
27 g --------  x
x = 34,61 %

OXIGENO
78 g ----- 100 %
48 g -----    x
x = 61.53 %

HIDROGENO
78 g ----- 100 %
  3 g -----    x
x = 3.84 %