Question

.....hola me ayudan​

Answer 1

Respuesta:

$(3a + 3b) ^{2} = 9 {a}^{2} + 18ab + 9 {b}^{2}$

$(2 - 2b) ^{2} = {4} - 8b + 4 {b}^{2}$

$(2x - y)(2x + y) = 4 {x}^{2} - {y}^{2}$

$formula \\ (x + y) ^{3} = {x}^{3} + 3 {x}^{2}y + 3x {y}^{2} + {y}^{3} \\ \\ (2 + \frac{1}{2}b) ^{3} =8 + 3 ({2})^{2} ( \frac{1}{2} b) + 3(2)( \frac{1}{2} b) ^{2} + ( \frac{1}{2} b) ^{3} \\ (2 + \frac{1}{2} b) ^{3} = 8 + 6b + \frac{ 3}{2} b ^{2} + \frac{1}{8} b ^{3}$

$formula \\ (x + y) ^{2} = {x}^{2} + 2xy + {y}^{2}$

La última pa ti mano no soy tu hincha

Saludos