Question

buenos dias el que sepa resolver logaritmos ¿me ayuda? por favor

f380018750504bc22860c09441fbe452.docx

Answer 1

Explicación paso a paso:

a) log3(x+3) - log3(x-1) =2

$log_{3}(x + 3) - log_{3}(x - 1) = 2$

$log_{3}( \frac{x + 3}{x - 1} ) = 2$

${3}^{2} = \frac{x + 3}{x - 1}$

9x-9 = x+3

8x = 12

x = 3/2

b) log2(x-2) - log2(x+1) = 3

$log_{2}(x - 2) - log_{2}(x + 1) = 3$

$log_{2}( \frac{x - 2}{x + 1} ) = 3$

${2}^{3} = \frac{x - 2}{x + 1}$

8x+8 = x -2

7x = -10

x = -10/7