Question

1.Determinar el conjunto M:

Answer 1

Respuesta:

C) {b;c}

Explicación paso a paso:

[(ax²+abc+abc)-(acx+abc+abx)]+[(3ax²+3abc+3abc)-(3acx+3abc+3abx)] = 0

[(ax²+abc+abc)-(acx+abc+abx)]+3[(ax²+abc+abc)-(acx+abc+abx)] = 0

4[(ax²+abc+abc)-(acx+abc+abx)] = 0

(ax²+abc+abc)-(acx+abc+abx) = 0

a[(x²+bc)-(cx+bx)] = 0

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Si a≠0

(x²+bc)-(cx+bx) = 0

x² + bc - (b+c)x = 0

x² - (b+c)x +bc= 0

(x-b)(x-c) = 0

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• x = b
• x = c

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Alternativa

C) {b;c}