Question

ayudaaaa os doy estrellita si esta bien

Answer 1

Respuesta:

$\boxed{\mathsf{10-2*\left[\sqrt{25}*3-(-4)+3^{2}\right]=-46\,\,,\frac{3-\frac{1}{2}*\frac{2}{5}}{(1-0.6)*3}=7\,\,,\frac{2}{3}:\frac{4}{5}-\left[\frac{1}{2}*3-\frac{3}{7}\right]=-\frac{140}{57}}}$

Explicación paso a paso:

$10-2*\left[\sqrt{25}*3-(-4)+3^{2}\right]\\\texttt{Realizando primero las operaciones entre corchetes}\\\texttt{y despu\'es multiplicarlas por 2 y sumarle 10}\\\\\left[\sqrt{25}*3-(-4)+3^{2}\right]=\left[5*3+4+9\right]=\left[15+4+9\right]=\\\\=[28]\\\\10-2*\left[\sqrt{25}*3-(-4)+3^{2}\right]=10-2[28]=10-56=-46\\\\b).-\\\frac{3-\frac{1}{2}*\frac{2}{5}}{(1-0.6)*3}=\frac{3-\frac{2}{10}}{\left(1-\frac{6}{10}\right)*3}=\frac{3-\frac{1}{5}}{\left(1-\frac{3}{5}\right)*3}=\frac{\frac{15}{5}-\frac{1}{5}}{\frac{5}{5}-\frac{3}{5}}=\\\\=\frac{\frac{14}{5}}{\frac{2}{5}}=\frac{(14)(5)}{(2)(5)}=7$

$c).-\\\frac{2}{3}:\frac{4}{5}-\left[\frac{1}{2}*3-\frac{3}{7}\right]=\frac{\frac{2}{3}}{\frac{4}{5}-\left[\frac{1}{2}*3-\frac{3}{7}\right]}=\frac{\frac{2}{3}}{\frac{4}{5}-\left[\frac{3}{2}-\frac{3}{7}\right]}=\\\\=\frac{\frac{2}{3}}{\frac{4}{5}-\left[\frac{15}{14}\right]}=\frac{\frac{2}{3}}{\frac{4}{5}-\frac{15}{14}}=\frac{\frac{2}{3}}{-\frac{19}{70}}=-\frac{(2)(70)}{(3)(19)}=\\\\=-\frac{140}{57}$