Question

Hallar X

De: 3,4,5 y 6

Answer 1

Explicación paso a paso:

3.

$\alpha = 5x - 30°.......(i) \\ \alpha = 7x - 50°......(ii)$

• igualamos las ecuaciones i y ii

$7x - 50° = 5x - 30° \\ 7x - 5x = - 30° + 50° \\ 2x = 20° \\ x = 10°$

4.

$70° + 130° + 100° + x = 360° \\ x = 360° - 300° \\ x = 60°$

5.

Sabiendo

$x = 180° - (\alpha + \theta)$

Determinando el valor de x

$130° + 70° + 2 \alpha + 2 \theta = 360° \\ 2 \alpha + 2 \theta \: = 360° - 200° \\ 2 \alpha + 2 \theta = 160° \\ simplificando \: la \: expresion \\ \alpha + \theta = 80°$

$x = 180° - 80° \\ x = 100°$

6.

$4x - 10° + 3x + 2x + 3° + x - 3° = 360° \\ 10x = 360° + 10° \\ 10x = 370° \\ x = 37°$