• Asignatura: Matemáticas
  • Autor: sandrarodriguez01
  • hace 4 años

10 – (8 + 4) =
3.b) 6 – (3 – 12) =
3.c) (5 + 7) – (2 – 8) =
3.d) 18 + (3 – 5 + 2 – 8) =
15 – (8 – 2 – 6 + 1) =
(5 – 3 + 2) – (10 – 5 – 3 + 1) =
(4 – 6) – [(–2) + (–7)] =
(–9) + [(–4) – (–2) + (–3)] =
(+12) – [(+2) + (–7) – (+14)] =
[(–12) – (–20)]– [(+6) + (5 – 9) – (16 – 8 – 11)] =
cuanto dan es urgentisimo

Respuestas

Respuesta dada por: geraldinebolano1
1

1.10−(8+4)

=10−12

=−2

2.

6−(3−12)

=6−(−9)

=15

3.5+7−(2−8)

=12−(2−8)

=12−(−6)

=18

4.18+3−5+2−8

=18+−2+2−8

=18+0−8

=18+−8

=10

5.15−(8−2−6+1)

=15−(6−6+1)

=15−(0+1)

=15−1

=14

6.=2+2−(10−5−3+1)

=4−(10−5−3+1)

=4−(5−3+1)

=4−(2+1)

=4−3

=1

7.=−2−(−2−7)

=−2−(−9)

=7

8.=−9+−2−3

=−9+−5

=−14

9.=12−(−5−14)

=12−(−19)

=31

10.=8−(6+5−9−(16−8−11))

=8−(6+−4−(16−8−11))

=8−(2−(16−8−11))

=8−(2−(8−11))

=8−(2−(−3))

=8−5

=3

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