Question

Secundaria
Desarrolla los binomios
(4y+3)3=
(2x-5y)3=
(1/4m2-1/2n3)3
(ax+1+1/2bx)3

Answer 1

1.

=(4y+3)(3)

=(4y)(3)+(3)(3)

=12y+9

2.=(2x+−5y)(3)

=(2x)(3)+(−5y)(3)

=6x−15y

3.

$= ( \frac{1}{4} {m}^{2} + \frac{ - 1}{2} {n}^{3} )(3)$

$=( \frac{1}{4} {m}^{2} )(3) + ( \frac{ - 1}{2} {n}^{3} )(3)$

$= \frac{3}{4} {m}^{2} + \frac{ - 3}{2} {n}^{3}$

$= \frac{ - 3}{2} {n}^{3} + \frac{3}{4} {m}^{2}$

$(Decimal: -1.5n^{3}+0.75m^{2})$

4.

$=(ax)(3)+(1)(3)+(( \frac{1}{2} b)(x))(3)$

$= 3ax+3+ \frac{3}{2} bx$

$= 3ax+ \frac{3}{2} bx + 3$

$(Decimal: 3ax+1.5bx+3)$