Question

determina el término faltante

AYUDA PORFAVOR ​

Answer 1

Respuesta:

$\boxed{\mathbf{\left\lbrace\left[\left(-\pi^{3}\right)^{\fbox{0}}\right]^{8}\right\rbrace}}\\\\\boxed{\mathbf{3^{6}\times3^{\fbox{-4}}=9}}\\\\\boxed{\mathbf{\sqrt[3]{\sqrt[\fbox{4}]{\phi^{5}}}=\phi^{5/12}}}\\\\\boxed{\mathbf{\sqrt[7]{6^{\fbox{21}}}=6^{3}}}$

Explicación paso a paso:

$\left\lbrace\left[\left(-\pi^{3}\right)^{\fbox{}}\right]^{8}\right\rbrace=1\\\left\lbrace\left[\left(-\pi^{3}\right)^{\fbox{0}}\right]^{8}\right\rbrace=1\\\\\left\lbrace-\pi^{3*0*8}\right\rbrace=1\\\\\left\lbrace-\pi^{0}\right\rbrace=1\\\\1=1\\\\3^{6}\times3^{\fbox{}}=9\\3^{6}\times3^{-4}=9\\3^{6-4}=9\\3^{2}=9\\9=9\\\\\sqrt[3]{\sqrt[\fbox{}]{\phi^{5}}}=\phi^{5/12}\\\left(\left(\phi^{5}\right)^{1/4}\right)^{1/3}=\phi^{5/12}\\\phi^{5*1/4*1/3}=\phi^{5/12}\\\phi^{5/12}=\phi^{5/12}\\\\\sqrt[7]{6^{\fbox{}}}=6^{3}\\\left(\left(6^{21}\right)\right)^{1/7}=6^{3}\\6^{21*1/7}=6^{3}\\6^{3}=6^{3}$