Question

me ayudan a derivar f(x)= x^2/1+e^x​

Answer 1

Respuesta:

f´(x) = (2x + 2x.eˣ - x².eˣ)/(1+eˣ)²

f"(x) = (2 + 2.eˣ - x² - eˣ) . (1+eˣ)²- (2x + 2x.eˣ - x².eˣ). eˣ/(1+eˣ)⁴

Explicación paso a paso:

f(x) = x²/(1+eˣ)

f´(x) = [2x . (1+eˣ) - x² . eˣ]/(1+eˣ)²

f´(x) = (2x + 2x.eˣ - x².eˣ)/(1+eˣ)²

f"(x) = (2 + 2.eˣ + 2x . eˣ - 2x . eˣ - x² - eˣ) . (1+eˣ)²- (2x + 2x.eˣ - x².eˣ). eˣ/(1+eˣ)⁴

f"(x) = (2 + 2.eˣ - x² - eˣ) . (1+eˣ)²- (2x + 2x.eˣ - x².eˣ). eˣ/(1+eˣ)⁴