• Asignatura: Matemáticas
  • Autor: sotomusopreitymilena
  • hace 5 años

Operaciones combinadas suma resta multiplicación de
números enteros
3) –6{5 – [5 (14 – 12) – 21+2(11 – 9)]} =

4) 4{10 – [10 (5 + 10) – 18–3(4 – 7)]} =
5) 9 – [10–3(– 5 + 2) +2(– 5 + 9)] =

6) – {8 + [9 + (13–14)]} =
7) – 6 – [(6 + 9 – 12) + (21–15)] =

8) –7 [ – 2(–4+3) –7]-57+ 1(11–25)
9) 12–{6+3[5-(8-7) –2(–4+3) –2]} =

10) 856–{17–2 [6+(5–3) –3(2–7) + 4(5-8)]}

Respuestas

Respuesta dada por: rebecaIsabelbts
5

Respuesta:

3) –6{5 – [5 (14 – 12) – 21+2(11 – 9)]}  =

–6{5 – [5 + 2 – 21+2 + 2]} =

–6{5 – [ 7 – 23 + 2]} =

–6{5 – [ 7 – 25]} =

–6{5 – [ -18]} =

–6{5 + 18} =

–6{23} =

–6 +23 =

17

4) 4{10 – [10 (5 + 10) – 18–3(4 – 7)]} =

4{10 – [10 + 15 – 18–3 –3]} =

4{10 – [10 + 15 – 18–6]} =

4{10 – [10 + 15 – 24]} =

4{10 – [25 - 24]} =

4{10 – 1} =

4 + 9  =

13

5) 9 – [10–3(– 5 + 2) +2(– 5 + 9)] =

9 – [10–3 –3 +2 + 4] =

9 – [10–3 –3 + 6] =

9 – [7 –3 + 6] =

9 – [4 + 6] =

9 – 10 =

-1

6) – {8 + [9 + (13–14)]} =

– {8 + [9 -1]} =

– {8 +8} =

– {16} =

-16

7) – 6 – [(6 + 9 – 12) + (21–15)] =

– 6 – [(15 – 12) + 6] =

– 6 – [3 + 6] =

– 6 – 9=

-15

8) –7 [ – 2(–4+3) –7]-57+ 1(11–25)

–7 [ – 2 -1 –7]-57+ 1 -14

–7 [ –10]- 57+ 1 -14

–7  –10- 57+ 1 -14

–7  –10- 57+ -13

–17- 57 -13

-87

9) 12–{6+3[5-(8-7) –2(–4+3) –2]} =

12–{6+3[5 -  1 –2 –1 –2]} =

12–{6+3 -1} =

12–{9 -1} =

12–8 =

4

10) 856–{17–2 [6+(5–3) –3(2–7) + 4(5-8)]}

856–{17–2 [6+2 –3 - 5 + 4 - 3]}

856–{17–2 [8 –3 - 9 - 3]}

856–{17–2 -7}

856–8

848

Coronita  plis :)


sotomusopreitymilena: gracias wey ::,D
rebecaIsabelbts: De nada
Preguntas similares