Question

2 log a + log 3 = log 48

Answer 1

Hola.

Tenemos

$2*log(a) + log(3) = log(48)$

$2*log(a) = log(48) - log(3)$      $====>$ $log(x) - log(y) = log(\frac{x}{y})$

$2*log(a) = log(\frac{48}{3})$

$2 * log(a) = log(16)$

$log(a) = \frac{log(16)}{2}$

$log(a) = \frac{ 1.20412}{2}$

$log(a) = 0.60206$       $=====>$  $log_{x}y = z$ $====>$ $x^{z}=y$

$10^{0.60206}=a$

$4 = a$

R.  a = 4

Un cordial saludo.