Question

Si a @ b = 3a + 4b y b % a = 6a + 2b, determina x
en: (x@2)%3 = 40.

Answer 1

(3x+4(2))%3 = 40

3x+8%3= 6(3) + 2(3x+8) = 40

18+6x+16=40

34+6x=40

6x=40-34

6x=6

x=1