Question

Calcular la fracción molar de una disolución en agua al 12,5% en peso de metanol
(CH3OH):

Answer 1

Respuesta:

Mm CH3OH = 32 g/mol

H2O = 18 g/mol

1. calcular gramos de metanol a partir del %

g = 12.5 / 100 = 0.125 g metanol

2. gramos de agua

g = 1g - 0.125 = 0.875 g agua

3. calcular moles:

n CH3COH = 0.125 g / 32 g/mol = 0.004 mol

n H2O = 0.875 g/18 g/mo = 0.05 mol

4. calcular moles totales (nt)

nt = 0.004 moles + 0.05 moles = 0.054 moles

5. calcula X (fracción molar)

Xsto = 0.004 mol

````````````````0.054 mol

Xsto = 0.07 (metanol9

Xsvte = 0.05 mol

````````````````

0.054 mol

Xsvte = 0.93