Question

Operaciónes combinadas de enteros :
$32 \div (6 - 2 {}^{2}) - \sqrt{36 + 3 \times ( - 5)} =$
$\sqrt{49 + (5 \times 6 - 3 {}^{3} } ) \div ( -7 + 2 \times 5) =$
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Answer 1

Respuesta:

$32 \div (6 - 2^2) - \sqrt{36 + 3 \times (-5)}$

$= 32 \div (6 - 4) - \sqrt{36 -15}$

$= 32 \div 2 - \sqrt{21}$

$= 16 - \sqrt{21}$

$\sqrt{49+(5\times 6 -3^3)}\div (-7 + 2 \times 5)$

$\sqrt{49+(30-27)}\div (-7 + 10)$

$\sqrt{49+3}\div 3$

$=\sqrt{52} \div3$

$=2\sqrt{13}\div 3$

$=\frac{2}{3}\sqrt{13}$