Question

Ayuda por favor!! estoy en examen!

Answer 1

Por extensión:

x = 4, 5, 6, 7, 8, 9, 10, 11

Reemplazo

$\frac{x+1}{2} = \frac{4+1}{5} = \frac{5}{5} = 1$     si ∈ IN

$\frac{x+1}{2} = \frac{5+1}{5} = \frac{6}{5}$            no ∉ IN

$\frac{x+1}{2} = \frac{6+1}{5} = \frac{7}{5}$            no ∉ IN

$\frac{x+1}{2} = \frac{7+1}{5} = \frac{8}{5}$             no ∉ IN

$\frac{x+1}{2} = \frac{9+1}{5} = \frac{10}{5} = 2$     si ∈ IN

$\frac{x+1}{2} = \frac{10+1}{5} = \frac{11}{5}$           no ∉ IN

$\frac{x+1}{2} = \frac{11+1}{5} = \frac{12}{5}$           no ∉ IN

A = {1, 2}

La suma es 1 + 2 = 3

Eternamente axllxa