Question

33 Calcula la solución de estas ecuaciones.

a) 7x - 2.(x + 1) = 0 d) 6x + 5.(1 - 3x) = 12 (×=....)

b) 3x + 4.5 - 2x) = -2 e) X-3.(x - 2) = 10 (×=....)

C) 5x - 3.(9-x) = 4 f) 2x + 7.(x + 4) = 19 (×=....)

D)6× + 5.(1 - 3×)= 12 (×=....)

e) × - 3 .( × - 2)=10 (×=....)

f) 2× + 7 . (× + 4)=19 (×=....)​

Answer 1

Respuesta:

$7x - 2(x + 1) = 0 \\ 7x - 2x - 2 = 0 \\ 5x = 2 \\ x = \frac{2}{5}$

$6x + 5(1 - 3x) = 12 \\ 6x + 5 - 15x = 12 \\ 5 - 12 = 15x - 6x \\ - 7 = 9x \\ \frac{ - 7}{9} = x$

$3x + 4 ( 5 - 2x) = - 2 \\ 3x + 20 - 8x = - 2 \\ 20 + 2 = 8x - 3x \\ 22 = 5x \\ \frac{22}{5} = x$

$x - 3(x - 2) = 10 \\ x - 3x + 6 = 10 \\ 6 - 10 = 3x - x \\ - 4 = 2x \\ - 2 = x$

$5x - 3(9 - x) = 4 \\ 5x - 27 + 3x = 4 \\ 8x = 4 + 27 \\ 8x = 31 \\ x = \frac{31}{8}$

$2x + 7(x + 4) = 19 \\ 2x + 7x + 28 = 19 \\ 9x = 19 - 28 \\ 9x = - 9 \\ x = - 1$

$6x + 5(1 - 3x) = 12 \\ 6x + 5 - 15x = 12 \\ 5 - 12 = 15x - 6x \\ - 7 = 9x \\ \frac{ - 7}{9} = x$

$x - 3(x - 2) = 10 \\ x - 3x + 6 = 10 \\ 6 - 10 = 3x - x \\ - 4 = 2x \\ - 2 = x$

$2x + 7(x + 4) = 19 \\ 2x + 7x + 28 = 19 \\ 9x = 19 - 28 \\ 9x = - 9 \\ x = - 1$