Question

4.- Resuelve las siguientes ecuaciones:



a) 3x – 3 = 5x + 7



b) 2x + 6 = x + 4



c) 4x – 7 = 3x + 1



d) 5x – 4 = 4x – 3

e)

$2m + {7}^{2} - \sqrt[3]{27} + 3m = - 6 + {2}^{5}$
Ayuda porfa es para hoy (╥﹏╥)
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Answer 1

Respuesta:

a)3x – 3 = 5x + 7

-3-7 = 5x-3x

-10 = 2x

-5 = x

b) 2x + 6 = x + 4

2x-x = 4-6

x = -2

c) 4x – 7 = 3x + 1

4x-3x = 1+8

x = 9

d) 5x – 4 = 4x – 3

5x-4x = -3+4

x = 1

Explicación paso a paso:

$2m - {7}^{2} + \sqrt[3]{27} + 3m = - 6 + {2}^{5} \\ 2m - 49 + 3 + 3m = - 6 + 32 \\ 5m - 46 = - 6 + 32 \\ 5m = - 6 + 32 + 46 \\ 5m = 72 \\ m = \frac{72}{5}$