Question

cual es el área y el perímetro de este circulos.​

Answer 1

Respuesta:

Espero haber podido ayudarte .

Explicación paso a paso:

1) r = 11m

 A = π × $r^{2}$                  P = 2 × π × r

 A = $11^{2}$ π                   P = 2 × π × 11

 A = 121 π$m^{2}$              P = 22 π m

2) r = 15 m ÷ 2 = 7,5 m

A = π × $r^{2}$                  P =  2 × π × r

A = π × $7.5^{2}$               P = 2 × π × 7.5

A = 56.25 π$m^{2}$         P = 15 π m

3) r = 14 m ÷ 2 = 7 m

A = π × $r^{2}$                 P = 2 × π × r

A = π × $7^{2}$                 P = 2 × π × 7

A = 49 π $m^{2}$             P = 14 πm

4) r = 1 m

A =  π × $r^{2}$                P = 2 × π × r

A = π × $1^{2}$                 P = 2 × π × 1

A = π $m^{2}$                  P = 2 π m

5) r = 3 m ÷ 2 = 1.5 m

A =  π × $r^{2}$               P = 2 × π × r

A = π × $1.5^{2}$             P = 2 × π × 1.5

A = 2.25 π$m^{2}$         P = 30 π m

6) r = 23 m ÷ 2 = 12.5 m

A = π × $r^{2}$               P = 2 × π × r

A = π × $12.5^{2}$          P = 2 × π ×  12.5

A = 156.25 π$m^{2}$    P = 30 π m

7) r = 10 m

A = π × $r^{2}$              P = 2 × π × r

A = π × $10^{2}$            P = 2 × π × 10

A = 100 π $m^{2}$        P = 20 π m

8) r = 5 m

A = π × $r^{2}$            P = 2 × π × r

A = π × $5^{2}$            P = 2 × π × 5

A = 25 π $m^{2}$        P = 10 π m

9) r = 9 m

A =  π × $r^{2}$             P = 2 × π × r

A = π × $9^{2}$              P = 2 × π × 9

A = 81 π $m^{2}$           P = 18 π m

10 ) r = 29 m ÷ 2 = 14.5 m

A =  π × $r^{2}$               P = 2 × π × r  

A = π × $14.5^{2}$            P = 2 × π × 14.5

A = 210.25 π $m^{2}$     P = 29 π m