1) (x + 5)(x - 2) = 0
2) 3y^2 + 8y - 9 = 2y
3) 9x^2 - 4 = 0
4) a^2 – 14a = -45
5) z(2z -3) = 14
6) x^3 – 22x = 9x^2
Me ayudan plsss
Respuestas
Respuesta:
Explicación paso a paso:
1) (x + 5)(x - 2) = 0
x+5=0 x-2=0
x= -5 x-2=0
x1 = -5 x2= 2
2) 3y^2 + 8y - 9 = 2y
3y^2 + 8y - 9 - 2y = 0
3y^2 +6 y - 9 = 0
y^2 + 2y -3 = 0
y^2 + 3y - y - 3 = 0
y * (y + 3) - y - 3 = 0
y * (y + 3) - (y + 3) = 0
(y + 3) * (y - 1) = 0
y + 3 = 0 y - 1 = 0
y1 = -3 y2 = 1
3) 9x^2 - 4 = 0
9x^2=4
x^2=4/9
x= ± 2/3
x1 = - 2/3 x2 = 2/3
4) a^2 – 14a = -45
a^2-14a+45=0
a^2-5a-9a+45=0
a*(a-5)-9a+45=0
a*(a-5)-9(a-5)=0
(a-5)*(a-9)=0
a-5=0 a-9=0
a1 =5 a2 =9
5) z(2z -3) = 14
2z-3=7
2z=7+3
2z=10
z=10/2
z=5
6) x^3 – 22x = 9x^2
x^3 – 22x-9x^2=0
x*(x^2-22-9x)=0
x*(x^2-9x-22)=0
x*(x^2+2x-11x-22)=0
x*(x*(x+2)-11x-22))=0
x*(x*(x+2)-11(x+2))=0
x*(x+2)*(x-11)=0
x=0 x+2=0 x-11=0
x=0 x=-2 x=11
x1 = -2
x2 = 0
x3 = 11