Question

(x^3 y^2 -462z)^6
¿Cómo resuelvo esta operación?​

Answer 1

Respuesta:

no esta bien escrito

Explicación paso a paso:

Answer 2

Respuesta:

(x^3 y^2 -462z)^6

$\left(x^3y^2-462z\right)^6$

Para resolver este caso se aplicaría el teorema del binomio:

$=\sum _{i=0}^6\binom{6}{i}\left(x^3y^2\right)^{\left(6-i\right)}\left(-462z\right)^i$

$=\frac{6!}{0!\left(6-0\right)!}\left(x^3y^2\right)^6\left(-462z\right)^0+\frac{6!}{1!\left(6-1\right)!}\left(x^3y^2\right)^5\left(-462z\right)^1+\frac{6!}{2!\left(6-2\right)!}\left(x^3y^2\right)^4\left(-462z\right)^2+\frac{6!}{3!\left(6-3\right)!}\left(x^3y^2\right)^3\left(-462z\right)^3+\frac{6!}{4!\left(6-4\right)!}\left(x^3y^2\right)^2\left(-462z\right)^4+\frac{6!}{5!\left(6-5\right)!}\left(x^3y^2\right)^1\left(-462z\right)^5+\frac{6!}{6!\left(6-6\right)!}\left(x^3y^2\right)^0\left(-462z\right)^6$  Y simplificamos

$=x^{18}y^{12}-2772x^{15}y^{10}z+3201660x^{12}y^8z^2-1972222560x^9y^6z^3+462^4\cdot \:15x^6y^4z^4-462^5\cdot \:6x^3y^2z^5+462^6z^6$

Explicación paso a paso:

espero te ayude