Question

como se resuelve  log(x-8)+log(x-2)=log (8-x)

Answer 1

log(x-8)+log(x-2)=log (8-x)
log (x-8)(x-2) = log (8-x)

(x-8)(x-2) = 8-x

x² - 10x + 16 = 8 - x

x² - 9x + 8 =0

(x-8)(x-1) =0


=> x = 8  ó    x =1


CS : {1;8}