Question

х²– х = 6
2ax - 3х + 4а - 6​

Answer 1

х²– х = 6

х²– х - 6 = 0

x         - 3

x          + 2

(x - 3)(x+2) = 0

x - 3 =  0            x + 2 = 0

x = 3                  x = -2

CS = (-2; 3)

2ax - 3х + 4а - 6​

2ax + 4a - 3x - 6

2a(x + 2)  - 2(x + 2)

(x +2)(2a - 1)

Eternamente axllxa