Question

-6,3(x-1)+3,5(3+4x)=10x
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Answer 1

Tenemos la ecuación:

$-6,3(x-1)+3,5(3+4x)=10x$

Pasamos los números decimales a fracciones:

$-\frac{63}{100} (x-1)+\frac{35}{100}(3+4x) =10x\\\\-\frac{63}{100} (\frac{x-1}{1}) +\frac{35}{100}(\frac{3+4x}{1})=10x\\\\-\frac{63(x-1)}{100} +\frac{35(3+4x)}{100} =10x$

Multiplicamos toda la ecuación por 100:

$100(-\frac{63(x-1)}{100} +\frac{35(3+4x)}{100} =10x)\\\\-63(x-1)+35(3+4x)=1000x$

Ya que tenemos una ecuación más entendible, la resolvemos:

$-63(x-1)+35(3+4x)=1000x\\\\-63x+63+105+140x=1000x\\\\77x+168=1000x\\168=1000x-77x\\\\168=923x\\\\\frac{168}{923} =x\\\\0,182=x$

x vale 0,182

Answer 2

Respuesta:

Tenemos la ecuación:

-6,3(x-1)+3,5(3+4x)=10x−6,3(x−1)+3,5(3+4x)=10x

Pasamos los números decimales a fracciones:

\begin{gathered}-\frac{63}{100} (x-1)+\frac{35}{100}(3+4x) =10x\\\\-\frac{63}{100} (\frac{x-1}{1}) +\frac{35}{100}(\frac{3+4x}{1})=10x\\\\-\frac{63(x-1)}{100} +\frac{35(3+4x)}{100} =10x\end{gathered}

−

100

63

(x−1)+

100

35

(3+4x)=10x

−

100

63

(

1

x−1

)+

100

35

(

1

3+4x

)=10x

−

100

63(x−1)

+

100

35(3+4x)

=10x

Multiplicamos toda la ecuación por 100:

\begin{gathered}100(-\frac{63(x-1)}{100} +\frac{35(3+4x)}{100} =10x)\\\\-63(x-1)+35(3+4x)=1000x\end{gathered}

100(−

100

63(x−1)

+

100

35(3+4x)

=10x)

−63(x−1)+35(3+4x)=1000x

Ya que tenemos una ecuación más entendible, la resolvemos:

\begin{gathered}-63(x-1)+35(3+4x)=1000x\\\\-63x+63+105+140x=1000x\\\\77x+168=1000x\\168=1000x-77x\\\\168=923x\\\\\frac{168}{923} =x\\\\0,182=x\end{gathered}

−63(x−1)+35(3+4x)=1000x

−63x+63+105+140x=1000x

77x+168=1000x

168=1000x−77x

168=923x

923

168

=x

0,182=x

x vale 0,182

Explicación paso a paso:

Tenemos la ecuación:

-6,3(x-1)+3,5(3+4x)=10x−6,3(x−1)+3,5(3+4x)=10x

Pasamos los números decimales a fracciones:

100

63

(x−1)+

100

35

(3+4x)=10x

−

100

63

(

1

x−1

)+

100

35

(

1

3+4x

)=10x

−

100

63(x−1)

+

100

35(3+4x)

=10x

Multiplicamos toda la ecuación por 100:

\begin{gathered}100(-\frac{63(x-1)}{100} +\frac{35(3+4x)}{100} =10x)\\\\-63(x-1)+35(3+4x)=1000x\end{gathered}

100(−

100

63(x−1)

+

100

35(3+4x)

=10x)

−63(x−1)+35(3+4x)=1000x

Ya que tenemos una ecuación más entendible, la resolvemos:

\begin{gathered}-63(x-1)+35(3+4x)=1000x\\\\-63x+63+105+140x=1000x\\\\77x+168=1000x\\168=1000x-77x\\\\168=923x\\\\\frac{168}{923} =x\\\\0,182=x\end{gathered}

−63(x−1)+35(3+4x)=1000x

−63x+63+105+140x=1000x

77x+168=1000x

168=1000x−77x

168=923x

923

168

=x

0,182=x

x vale 0,182