Question

AYUDENME ES LO ULTIMO QUE TENGO QUE HACER
A-m.c.m (12,32)=
b) DCM ( 48 , 60)=
c) m.c.m ( 14, 28, 60)=
d) DCM ( 6,10,24)

Answer 1

Respuesta:

mcm (12,32)= 192

dcm(48,60)= 12

mcm (14,28,60)= 420

dcm (6,10,24)= 2

Explicación paso a paso:

mcm (12,32)

$12 = {2}^{2} \times 3 \\ 32 = {2}^{6} \\ mcm(12 \: \: 32) = {2}^{6 \time} \times 3 = 192$

dcm (48,60)

$48 = {2}^{4} \times 3 \\ 60 = {2}^{2} \times 3 \times 5 \\ dcm(48 \: \: 60) = {2}^{2} \times 3 = 12$

mcm (14,28,60)

$14 = 2 \times 7 \\ 28 = {2}^{2} \times 7 \\ 60 = {2}^{2} \times 3 \times 5 \\ mcm(14 \: \: 28 \: \: 60) = {2}^{2} \times 3 \times 5 \times 7 = 420$

dcm=(6,10,14)

$6 = 2 \times 3 \\ 10 = 2 \times 5 \\ 24 = {2}^{3} \times 3 \\ dcm(6 \: \: 10 \: \: 24) = 2$