Question

Calcular la siguientes Sumatoria:
3
∑ (1)k+2 (2k+3)³
k=1

Answer 1

3 ∑ (1)k+2 (2k+3)³
k=1

reemplazando "k" según fórmula:
3(1(1) + 2[(2(1) + 3)al cubo]) = 3(1 + 2(2+3)al cubo) = 3(1+2(5)al cubo) = 3(1+2(125)) = 3(1+250) = 3(251) = 753