Question

Razones trigonometricaas

Answer 1

Respuesta:

Explicación paso a paso:

Aplicando Pitágoras:

AC² = CB² + BA²

15² = CB² + 5²

225 = CB² + 25

225 - 25 = CB²

200 = CB²

√200 = CB

cos A = 5/15

sen A = √200/15

$(\frac{cosA}{senA}-\frac{3}{12}) ^{2} =$

$(\frac{\frac{5}{15} }{\frac{\sqrt{200} }{15} }-\frac{3}{12} ) ^{2} =$

$(\frac{5}{\sqrt{200} }-\frac{3}{12}) ^{2} =$

(5/√200)² - 2 . 5/√200 . 3/12 + (3/12)² =

25/200 - 5/2√200 + 1/16 =

1/8 - 5 . √200/ 400 + 1/16 =

3/16 - √2/8 ≅ 0,0107