Question

3a^2b^3c(2a^4b^3c^2-3a^3b^2c+4a^2b-5a+13)​

Answer 1

HI...

3a2b3c(2a4b3c2−3a3b2c+4a2b−5a+13)

=(3a2b3c)(2a4b3c2+−3a3b2c+4a2b+−5a+13)

=(3a2b3c)(2a4b3c2)+(3a2b3c)(−3a3b2c)+(3a2b3c)(4a2b)+(3a2b3c)(−5a)+(3a2b3c)(13)

=6a6b6c3−9a5b5c2+12a4b4c−15a3b3c+39a2b3c

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