Question

formula empirica de 17.55% de na, 39.69 % de cr, 42.74 de o

Answer 1

Na = 23 g/mol
Cr = 52 g/mol
O = 16 g/mol

Na = 17.55 g / 23 g/mol = 0.7630 mol

Cr = 39,69 g  / 52 g/mol = 0.7632 mol

O = 42,74 g / 16 g/mol = 2.6713 mol

dividir cada elemento entre el menor de los resultados

Na = 0.7630 mol = 0.7630 mol = 1
Cr = 0.7632 mol / 0.7630 mol = 1
O = 2.6713 mol / 0.7630 mol = 4

FORMULA EMPIRICA = NaCrO4