Question

Si la recta M: 2x+y+6=0 es paralela a la recta N: kx-3y+1=0, entonces el valor de k es:

Answer 1

Respuesta:

Refer the attached graph below.

Step-by-step explanation:

Given : 2x+y-6=02x+y−6=0 and 4x-2y-4=04x−2y−4=0

To find : Graph of the equations?

Solution :

Let, Equation 1 - 2x+y-6=02x+y−6=0

and Equation 2- 4x-2y-4=04x−2y−4=0

Now, We find the x and y intercepts of the equation to plot the graph.

Equation 1 - 2x+y-6=02x+y−6=0

Put x=0,

\begin{gathered}2(0)+y-6=0\\y=6\end{gathered}

2(0)+y−6=0

y=6

Put y=0,

\begin{gathered}2x+0-6=0\\x=3\end{gathered}

2x+0−6=0

x=3

Points of equation 1 is (0,6) and (3,0)

Equation 2- 4x-2y-4=04x−2y−4=0

Put x=0,

\begin{gathered}4(0)-2y-4=0\\y=-2\end{gathered}

4(0)−2y−4=0

y=−2

Put y=0,

\begin{gathered}4x-2(0)-4=0\\x=1\end{gathered}

4x−2(0)−4=0

x=1

Points of equation 1 is (0,-2) and (1,0)

Now, we plot these two equations.

The graph of 2x+y-6=02x+y−6=0 is shown with red line.

The graph of 4x-2y-4=04x−2y−4=0 is shown with blue line.

The solution to this system will be their intersection point.

The intersection point of these graph is (2,2)

Refer the attached graph below.