Question

Derivada trigonométrica de
f(x) = sec (5x + 2)

Answer 1

Respuesta:

f´(x) = 5 tg (5x+2) . sec (5x+2)

Explicación paso a paso:

f(x) = sec (5x + 2)

f(x) = 1/cos(5x+2)

f´(x) = [0 . cos(5x+2) - 1 . (-sen (5x+2)) . 5]/cos² (5x+2)

f´(x) = 5 sen (5x+2)/ cos² (5x+2)

f´(x) = 5 sen (5x+2)/ cos (5x +2) . 1/ cos (5x+2)

f´(x) = 5 tg (5x+2) . sec (5x+2)