Question

Es del tema de factorizacion

Answer 1

$x^5+x+1 = (x^2+x+1)*(x^3-x^2+1) \\ \\Verificiaci\'on \\ \\ x^5+x+1 = (x^2+x+1)*(x^3-x^2+1) \\ \\ x^5+x+1 = (x^2*x^3-x^2*x^2+x^2*1)+(x*x^3-x*x^2+x*1) \\.\qquad \qquad \qquad +(1*x^3-1*x^2+1*1) \\ \\ x^5+x+1 = (x^5-x^4+x^2)+(x^4-x^3+x) +(x^3-x^2+1) \\ \\ x^5+x+1 = x^5-x^4+x^2+x^4-x^3+x +x^3-x^2+1 \\ \\ Cancelamos \ x^4, x^3 , x^2 \\ \\ x^5+x+1 = x^5+x+1 \ \checkmark \to Opci\'on \ e)$

Espero que te sirva, salu2!!!!