• Asignatura: Matemáticas
  • Autor: zuleykaandrade
  • hace 5 años

resuelve las siguientes ecuaciones:
de la 12 a la 16
plis rápido esq. tengo que subirlo a la 1

Adjuntos:

Respuestas

Respuesta dada por: NKRYZ
1

Respuesta:

12)14-\left(5x-1\right)\left(2x+3\right)=17-\left(10x+1\right)\left(x-6\right)

    -10x^2-13x+17=-10x^2+59x+23

    -10x^2-13x+17-17=-10x^2+59x+23-17

    -10x^2-13x=-10x^2+59x+6

    -10x^2-13x-\left(-10x^2+59x\right)=-10x^2+59x+6-\left(-10x^2+59x\right)

    -72x=6

    \frac{-72x}{-72}=\frac{6}{-72}

    x=-\frac{1}{12}

13)\left(x-2\right)^2+x\left(x-3\right)=3\left(x+4\right)\left(x-3\right)-\left(x+2\right)\left(x-1\right)+2

     2x^2-7x+4=2x^2+2x-32

     2x^2-7x+4-4=2x^2+2x-32-4

     2x^2-7x=2x^2+2x-36

     2x^2-7x-\left(2x^2+2x\right)=2x^2+2x-36-\left(2x^2+2x\right)

     -9x=-36

     \frac{-9x}{-9}=\frac{-36}{-9}

     x=4

14)\left(3x-1\right)^2-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)=0

    \left(3x-1\right)^2-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)

    =9x^2-6x+1-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)

    =9x^2-6x+1-5\left(x-2\right)-\left(4x^2+12x+9\right)-\left(5x+2\right)\left(x-1\right)

    =9x^2-6x+1-5x+10-\left(4x^2+12x+9\right)-\left(5x+2\right)\left(x-1\right)

    =9x^2-6x+1-5x+10-4x^2-12x-9-\left(5x+2\right)\left(x-1\right)

    =9x^2-6x+1-5x+10-4x^2-12x-9-5x^2+3x+2

    =-20x+4

    -20x+4=0

    -20x=-4

    \frac{-20x}{-20}=\frac{-4}{-20}

    x=\frac{1}{5}

15)2\left(x-3\right)^2-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)=4x^2-12

    2\left(x-3\right)^2-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)

    =2\left(x^2-6x+9\right)-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)

    =2\left(x^2-6x+9\right)-3\left(x^2+2x+1\right)+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)

    =2x^2-12x+18-3\left(x^2+2x+1\right)+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)

    =2x^2-12x+18-3x^2-6x-3+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)

    =2x^2-12x+18-3x^2-6x-3+x^2-8x+15+4\left(x^2-5x+1\right)

    =2x^2-12x+18-3x^2-6x-3+x^2-8x+15+4x^2-20x+4

    =4x^2-46x+34

    4x^2-46x+34=4x^2-12

    4x^2-46x+34-34=4x^2-12-34

    4x^2-46x=4x^2-46

    4x^2-46x-4x^2=4x^2-46-4x^2

    -46x=-46

    \frac{-46x}{-46}=\frac{-46}{-46}

    x=1

16)5\left(x-2\right)^2-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2=0

    5\left(x-2\right)^2-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2

    =5\left(x^2-4x+4\right)-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2

    =5\left(x^2-4x+4\right)-5\left(x^2+6x+9\right)+\left(2x-1\right)\left(5x+2\right)-10x^2

    =5x^2-20x+20-5\left(x^2+6x+9\right)+\left(2x-1\right)\left(5x+2\right)-10x^2

    =5x^2-20x+20-5x^2-30x-45+\left(2x-1\right)\left(5x+2\right)-10x^2

    =5x^2-20x+20-5x^2-30x-45+10x^2-x-2-10x^2

    =-51x-27

    -51x-27=0

    -51x=27

    \frac{-51x}{-51}=\frac{27}{-51}

    x=-\frac{9}{17}

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