Question

$45x^{2} -35x-8=0$

Answer 1

Respuesta:

$45x^2-35x-8=0$

$x_{1,\:2}=\frac{-\left(-35\right)\pm \sqrt{\left(-35\right)^2-4\cdot \:45\left(-8\right)}}{2\cdot \:45}$

$x_{1,\:2}=\frac{-\left(-35\right)\pm \sqrt{2665}}{2\cdot \:45}$

$x_1=\frac{-\left(-35\right)+\sqrt{2665}}{2\cdot \:45},\:x_2=\frac{-\left(-35\right)-\sqrt{2665}}{2\cdot \:45}$

$x=\frac{35+\sqrt{2665}}{90},\:x=\frac{35-\sqrt{2665}}{90}$