Question

Me ayudan por favor?

Answer 1

$Log_{\frac{1}{2} } \sqrt{2} = x\\\\(\frac{1}{2} )^{^{x} } = \sqrt{2} \\\\(2^{-1})^{x} = 2^{^{\frac{1}{2} } }\\\\2^{-x} = 2^{^{\frac{1}{2} } }\\\\-x =\frac{1}{2}\\\\ x = -\frac{1}{2}$

Eternamente axllxa