Question

Ejercicio combinados ahora con potenciacion y radicacion:
a - 10 + 4 . 3² =
b - 5 . √64 - 27 =
c - ( 11 - 7 ) ² + 5² =
d - 24 : √10 + 6 - 3 =
e - ( 3 . 2 + 1 ) ² + 8° =
f - ³√64 : 2 + 3³ - 11 =
g - 2 . √169 - 200 : 5² =
h - 6° + 5 . ( 20 - 6 . 3 ) $3^{4}$ =
i - 28 : √10 . 4 + 9 + 2 $2^{5}$ =

Answer 1

Respuesta:

yo no soy de secundaria asi que no se

Explicación paso a paso:

Answer 2

(Son las que pude

a-

$10 + 4 \times 3^{2} = \\ 10 + 4 \times 9 = \\ 10 + 36 = \\ 46$

b-

$5 \times \sqrt{64} - 27 = \\ 5 \times 8 - 27 = \\ 40 - 27 = \\ 13$

c-

$(11 - 7)^{2} + 5^{2} = \\ 4^{2} + 5 ^{2} = \\ 16 + 5^{2} = \\ 16 + 25 = \\ 41$

e-

$(3 \times 2 + 1)^{2} + {8}^{0} = \\ (6 + 1)^{2} + 8^{0} = \\ 7^{2} + 8 ^{0} = \\ 49 + 8^{0} = \\ 49 +1 = \\ 50$

f-

$\sqrt[3]{64} \div 2 + 3^{3} + 11 = \\ 4 \div 2 + 3^{3} + 11 = \\ 4 \div 2 + 27 + 11 = \\ 2 + 27 + 11 = \\ 29 + 11 = \\ 40$

g-

$2 \times \sqrt{169} - 200 \div 5 ^{2} = \\ 2 \times 13 - 200 \div 5 ^{2} = \\ 2 \times 13 - 200 \div 25 = \\ 26 - 200 \div 25 = \\ 26 - 8 = \\ 18$

$6^{0} + 5 \times (20 - 6 \times 3)3^{4} = \\ 6^{0} + 5 \times (20 - 18) \times 3^{4} = \\6^{0} + 5 \times 2 \times 3^{4} = \\ 1 + 5 \times 2 \times 3^{4} = \\ 1 + 5 \times 2 \times 81 = \\ 1 + 10 \times 81 = \\1 + 810 = \\ 811$