Question

me ayudan con el 4,6 y 8 por favor?):​

Answer 1

Hay nose :(( perdón

Answer 2

$4). \: ( \frac{1}{2} t - \frac{2}{3} ) {}^{3} = \\ ( \frac{1}{2} t) {}^{3} - 3 \times ( \frac{1}{2} t) {}^{2} \times \frac{2}{3} + 3 \times \frac{1}{2} t \times ( \frac{2}{3} ) {}^{2} - ( \frac{2}{3} ) {}^{3} = \\ \frac{1}{8} t {}^{3} - 3 \times \frac{1}{4} t {}^{2} \times \frac{2}{3} + 3 \times \frac{1}{2} t \times \frac{4}{9} - \frac{8}{27} = \\ \\ \frac{1}{8} t {}^{3} - \frac{1}{2} t {}^{2} + \frac{2}{3} t - \frac{8}{27} \\ \\ - - - - - - - - - - - - - - - - - - - \\ \\ 6). \: ( \sqrt{3 t} - \sqrt{3} ) {}^{2} = \\ 3 t - 2 \sqrt{9 t} + 3 = \\ 3 t - 2 \times 3 \sqrt{ t} + 3 = \\ \\ 3 t - 6 \sqrt{ t} + 3 \\ \\ - - - - - - - - - - - - - - - - - - - \\ \\ 8). \: ( - \frac{1}{2} t - \frac{1}{3} )( - \frac{1}{2} t + \frac{1}{3} ) = \\ ( - \frac{1}{2} t) {}^{2} - ( \frac{1}{3} ) {}^{2} = \\ \\ \frac{1}{4} t {}^{2} - \frac{1}{9}$