Question

lim/(t→0) (4t²+5t+2)/(t³+2t-6)=-1/3​

Answer 1

Respuesta:

lim/(t->0) (4(0)^2+5(0)+2)/(0^3+2(0)-6)=-1/3

(4×0+0+2)/(0+0-6)=-1/3

(0+2)/(-6)=-1/3

2/(-6)=-1/3

-2/6=-1/3

-1/3=-1/3