Question

2/3x²-1/2x-2+1/4x²-2/3x+1/3-5/6x²
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Answer 1

Respuesta:

$\frac{2}{3}x^2-\frac{1}{2}x-2+\frac{1}{4}x^2-\frac{2}{3}x+\frac{1}{3}-\frac{5}{6}x^2\\\\=\frac{2}{3}x^2+\frac{1}{4}x^2-\frac{5}{6}x^2-\frac{1}{2}x-\frac{2}{3}x+\frac{1}{3}-2\\\\=\frac{1}{12}x^2-\frac{1}{2}x-\frac{2}{3}x+\frac{1}{3}-2\\\\=\frac{1}{12}x^2-\frac{7}{6}x+\frac{1}{3}-2\\\\=\frac{x^2}{12}-\frac{7x}{6}+\frac{1}{3}-2\\\\=-\frac{5}{3}+\frac{x^2}{12}-\frac{7x}{6}\\\\=\frac{x^2}{12}-\frac{7x}{6}-\frac{5}{3}$

Explicación paso a paso: