Question

Como despejo m1 de esta ecuación??

Answer 1

$v_{2} =(\frac{2m_{1} }{m_{1}+m_{2} } )$

$v_{2} (m_{1} +m_{2} )= 2m_{1}$

$v_{2}m _{1} +v_{2} m_{2} = 2m_{1}$

$v_{2} m_{2} = 2m_{1} -v_{2} m_{1}$

$v_{2} m_{2} = m_{1} (2 - v_{2} )$

$m_{1} =\frac{v_{2} m_{2} }{2-v_{2} }$