Question

log4x=3log2+4log3
log(2x-4)=2
4log(3-2x)=-1

Answer 1

log4x=3log2+4log3
log4x = log2³ + log3^4
Log4x=log(8)(81)

=> 4x = 8 (81)
        x = 162


log(2x-4)=2
2x-4=10^2
2x-4=100
2x=104
x=52

4log(3-2x)=-1
log(3-2x) = -1/4
3-2x=10^{-1/4}
3-2x=1/raiz cuarta de 10
(3 - 1/raiz cuarta de 10 )/2  = x
x = 1,78 aprox