Question

Obtén la inecuacion equivalente del tipo xa, x≤a o x≥a a cada una de estas inecuaciones.
a) 5x < -15
b) 2x < 7/3
c) -7x ≤ -56
d) -3x/4 > -1/7
e) 3x+8/2 < x+20/5
f) x/2 -3 ≤ 5x/4 - 1/4
g) 8(x-1)/3 +7 > 6x-18/9
h) 4x/3 -2 ≤ x

por fa ayudenme
112 puntos es para hoy

Answer 1

$A) \\ 5x\ \textless \ -15 \\ X\ \textless \ \frac{-15}{5} \\ X\ \textless \ -3 \\ \\ B) \\ 2x\ \textless \ \frac{7}{3} \\ \\ X\ \textless \ \frac{7}{ \frac{3}{2} } \\ \\ X\ \textless \ \frac{7}{6} \\ \\ C) \\ (-1)-7x \leq -56(-1) \\ 7x \geq 56 \\ X \geq \frac{56}{7} \\ X \geq 8 \\ \\ D) \\ \frac{-3x}{4} \ \textgreater \ \frac{-1}{7} \\ -3x\ \textgreater \ 4( \frac{-1}{7} ) \\ -3x\ \textgreater \ \frac{-4}{7} \\ -x\ \<span>textless</span> \ \frac{-4}{ \frac{7}{3} } \\ -x\ \textgreater \ \frac{-4}{21}(-1) \\ X\ \textgreater \ \frac{4}{21}$
$E) \\ 3x+ \frac{8}{2} \ \textless \ x+ \frac{20}{5} \\ 3x-x\ \textless \ \frac{20}{5} - \frac{8}{2} \\ 3x-x\ \textless \ 4-4 \\ 2x\ \textless \ 0 \\ x\ \textless \ \frac{0}{2} \\ x\ \textless \ 0$
$F) \\ \frac{x}{2} -3 \leq \frac{5x}{4}- \frac{1}{4} \\ \frac{x}{2} -\frac{5x}{4} \leq 3- \frac{1}{4} \\ \frac{2x-5x}{4} \leq \frac{12-1}{4} \\ \frac{-3x}{4} \leq \frac{11}{4} \\ -3x \leq 4( \frac{11}{4}) \\ (-1)-3x \leq \frac{44}{4}(-1) \\ 3x \geq -11 \\ X \geq -\frac{11}{3}$
$G) \\ 8 \frac{(x-1)}{3+7}\ \textgreater \ 6x- \frac{18}{9} \\ \\ \frac{8x-8}{10}\ \textgreater \ 6x-2 \\ \\ 8x-8\ \textgreater \ 10(6x-2) \\ 8x-8\ \textgreater \ 60x-20 \\ 8x-60x\ \textgreater \ -20+8 \\ -52x\ \textgreater \ -12(-1) \\ 52x\ \textless \ 12 \\ X\ \textless \ \frac{12}{52} \\ \\ X\ \textless \ \frac{3}{13}$
$H) \\ \frac{4x}{3} -2 \leq x \\ \\ \frac{4x-6}{3} \leq x \\ \\ 4x-6 \leq 3x \\ 4x-3x \leq 6 \\ X \leq 6$