Question

(a²-3a;5)=(4;a+1)
entonces
$\sqrt{a}$
es​

Answer 1

(a² - 3a ; 5) = (4 ; a+1)

    5 = a +1

5 - 1 =  a

    4 = a

$\sqrt{a} = \sqrt{4} = 2$

Eternamente axllxa