Question

3(×-5)-4(4-3×)≥2(7-×)-3(×-5)
2(×-2)+8≤3(×+2)-12
2×+3(2-×)<16
5×-2<10×+8
3×(×-6)<4×-10
5(×-1)-2×≥2(×-4)+3
1-4(×-5)<×-9
5×-3(5-×)+6<1​

Answer 1

Explicación paso a paso:

3(×-5)-4(4-3×)≥2(7-×)-3(×-5)

3X-15-16+12X= 14-2X-3X+15

15X+2X+3X= 14+15+15+16

20X= 60

X= 60/20= 3

2(×-2)+8≤3(×+2)-12

2X-4+8= 3X+6-12

2X-3X= 6-12+4-8

-X= -20+10

-X= -10

X= 10

2×+3(2-×)<16

2X+6-3X= 16

-X= 16-6

-X= 10

X= -10

5×-2<10×+8

5X-2= 10X+8

5X-10X= 8+2

-5X= 10

X= 10/-5= -2

3×(×-6)<4×-10

3X2-18= 4X-10

3X2-4X-18+10= 0

3X2-4X-8= 0

A= 3. B= -4. C= -8.

X= -B+√B-4AC/2A

X= -(-4)+√(-4)-4(3)(-8)/2(3)

X= 4+√(-4)-4(3)(-8)/2(3)

X1= 4+√92/6= 4/6+√15.333= 4.58

X2= 4/6-√15.333= -3.25

5(×-1)-2×≥2(×-4)+3

5X-5-2X= 2X-8+3

3X-2X= -8+3+5

X= 0

1-4(×-5)<×-9

1-4X+20= X-9

4X-X= -9-1-20

3X= -21

X= -21/3= -7

5×-3(5-×)+6<1

5X-15+3X+6= 1

8X= 1+15-6

X= 10/8 = 5/4